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Theorem: ln(-1) = 0 Proof: By first focusing on the log rule, ln(-1)2 = 2ln(-1) But, by focusing first on the exponent, ln(-1)2 = ln(1) = 0 Thus, by the transitive property, 2ln(-1) = 0 Dividing both sides by 2, ln(-1) = 0 Q.E.D.
Proof:
By first focusing on the log rule, ln(-1)2 = 2ln(-1)
But, by focusing first on the exponent, ln(-1)2 = ln(1) = 0
Thus, by the transitive property, 2ln(-1) = 0
Dividing both sides by 2, ln(-1) = 0
Q.E.D.