Why 792?
If when a number is divided continuously by 8, 9, and 11 the remainders are 5, 2, and 4 respectively, what would be the remainder if the same number were divided by 792?
Solution: Suggested Solution (Kim Struiksma and Katie McClockey, WWU students)
How to solve the problem:
11x + 4 [Here x = 1 so (11)(1) + 4 = 15]
15 x 9 = 135
135 + 2 = 137
137 x 8 = 1096
1096 + 5 = 1101 [Step 5]
1101/792 = 1 remainder 309
You can use any integer value for x, and the quotient of the final number in Step 5 divided by 792 will be the chosen value of x with a remainder of 309.
Source: Charles Pendlebury's Arithmetic (London: G. Bell & Son, 1918)
