But You Can't Take Logs of Negative Numbers!
Theorem: ln(1) = 0
Proof:
By first focusing on the log rule, ln(1)^{2} = 2ln(1)
But, by focusing first on the exponent, ln(1)^{2} = ln(1) = 0
Thus, by the transitive property, 2ln(1) = 0
Dividing both sides by 2, ln(1) = 0
Q.E.D.
