Theorem: log(1) = 0
Proof:
First, by log properties, we know log[(1)^{2}] = 2 * log(1)
But, by exponent properties, log[(1)^{2}] = log(1) = 0
By the transitive property, 2* log(1) = log(1) = 0
Divide both sides by 2 to get log(1) = 0.
What's wrong?
