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Why 792?

If when a number is divided continuously by 8, 9, and 11
the remainders are 5, 2, and 4 respectively,
what would be the remainder if the same number were divided by 792?

Solution:

Suggested Solution (Kim Struiksma and Katie McClockey, WWU students)

How to solve the problem:

11x + 4 [Here x = 1 so (11)(1) + 4 = 15]

15 x 9 = 135

135 + 2 = 137

137 x 8 = 1096

1096 + 5 = 1101 [Step 5]

1101/792 = 1 remainder 309

You can use any integer value for x, and the quotient of the final number in Step 5 divided by 792 will be the chosen value of x with a remainder of 309.

Source: Charles Pendlebury's Arithmetic (London: G. Bell & Son, 1918)